Properties of logarithms

There are several rules that you will need to remember when it comes to logarithms. We will detail these more general rules as well as how to use logarithms in basic algebraic equations in this chapter.

Understanding logarithms

A logarithm is a function that describes the power to which a base must be raised in order to result in a certain number. This will make more sense as we understand how they are used in algebra.

For now, let’s examine the different parts of a logarithm that we will be talking about in this chapter:

$lo g_{2} (8) = 3$

In this example, the $2$ is what is called a base. The base of a logarithm is the smaller number that rests between the word “ $lo g$ ” and the parentheses. The $8$ is the number being operated on by the logarithm. $3$ is the answer we get when we solve “log base-2 of 8.”

Logarithm rules using parentheses

Multiplication

When there is multiplication inside the parentheses of a logarithm, it can make our calculations very complicated. So, we can rearrange it by taking each number being multiplied and creating a new logarithm for each one of them. Then, we sum together each of the new logarithms.

So, we can start out with a logarithm like this:

$lo g_{2} (8 * x)$

And rearrange it to look like this:

$lo g_{2} (8) + lo g_{2} (x)$

You’ll notice that both of the logarithms have the same base, $2$ . When you perform this expansion of logarithms, each term should have the same base.

Division

When there is division inside the parentheses of a logarithm, we follow a similar process as above but we subtract logarithms instead of adding them. We will keep all the bases the same, too.

Let’s expand the following logarithm using the same rules as multiplication, but subtracting instead of adding the terms:

$lo g_{2} (\frac{8}{x}) = lo g_{2} (8) - lo g_{2} (x)$

As you can see, the numerator is the first logarithm, then the denominator is subtracted from it.

Exponents

When there is an exponent inside the parentheses of a logarithm, we can reorganize it by taking the exponent out of the logarithm and multiplying it onto the front of the expression. The number that has the exponent will remain inside the parentheses; only the exponent will be shifted within the expression. Follow this in the example below:

$lo g_{2} (x^{8}) = 8 * lo g_{2} (x)$

We remove the exponent from inside the parentheses and put it in front of the logarithm. That’s all there is to it!

Reverse rules

We have talked about three rules concerning logarithms. We can use these rules to take things in the parentheses and move them out of the parentheses, or we can use the rules in the reverse way. You must remember that these rules are a two-way street. If you can rearrange a logarithm in a certain way, you have to be able to change it back, too. Look at the following few examples to get an idea of how to recognize these reverse rules:

Rewrite the following expression as a single logarithm

$lo g_{10} (8) + lo g_{10} (7) + lo g_{10} (x)$

You should recognize the addition of multiple logs with the same base. Our multiplication rule is what causes this expansion into a sum, so let’s perform that step backward to get our final, simplified answer:

$lo g_{10} (8 * 7 * x) = lo g_{10} (56 x)$

Simplify the following logarithmic expression:

$3 * lo g_{6} (x)$

(spoiler)

Use the exponent rule here. The exponent rule says that we remove the exponent from inside the parentheses and multiply it outside the logarithm. The reverse of this would be restoring the exponent.

Thus, our final answer is:

$lo g_{6} (x^{3})$

Change of base

If you must evaluate a logarithmic function with a base other than the usual $10$ , you may have trouble putting it into your calculator. Some calculators like the TI-84 are able to calculate logarithms of different bases, but others are not. We will review both of these cases.

Logarithms in a graphing calculator

For a TI-84, perform a logarithmic calculation by pressing the $lo g$ button, entering the number within the $lo g$ , a comma, and then the base of the $lo g$ .

In a calculator, this would look like $lo g ($ number, base $)$ . Let’s find the value of $lo g_{2} (30)$ . We do this by typing (without quotation marks) into our calculator “ $lo g (2, 30)$ .” This comes out to equal $4.9$ .

Change of base formula

If you need to calculate a logarithm with an abnormal base (a base other than $10$ ), use the following equation:

$lo g_{b} (a) = \frac{lo g _{x} ( a )}{lo g _{x} ( b )}$

The base of the logarithms in the new fraction is unimportant, so it can be any number greater than $1$ . It is best to make the base $10$ so that you can use the normal $l o g$ function in your calculator.

This being the case, we can edit the formula:

$lo g_{b} (a) = \frac{lo g _{10} ( a )}{lo g _{10} ( b )}$

Let’s evaluate $lo g_{2} (30)$ using this formula:

$lo g_{2} (30) = \frac{lo g _{10} ( 30 )}{lo g _{10} ( 2 )} = 4.9$

Logarithms in algebra

There will be times in which you will be asked to find the value of $x$ within a given logarithmic equation. This could be similar to the following form:

$lo g_{x} (9) = 2$

To solve for $x$ , we will go over one key concept of how to use logarithms in algebra without a calculator.

In order to solve this equation, we will get rid of the “ $lo g$ .” We do this by taking the base number, in the above example it is $x$ , and moving it to the right side of the equation. On the right side of the equation, we take all the values that started there and raise them as the power of the base. At this point, we may remove the “ $lo g$ ” from the equation. Follow along:

$lo g_{x} (9) 993 = 2 = x^{2} = x = x$

A handy way to remember this rule is that you are swapping the smaller number in the equation. At first, $x$ is the small number because it is the subscript or the base. We want to make the $x$ normal sized, and then make the right side of the equation the new small number by raising it as a superscript, or the exponent. Try a few more short examples of how to apply this to algebraic problems.

Examples

What is the value of $x$ ?

$lo g_{2} (x) = 4$

(spoiler)

Move the base ( $2$ ) to the right side and raise the $4$ as its exponent:

$lo g_{2} (x) x x = 4 = 2^{4} = 16$

Let’s try another!

Find the value of $x$ for the following equation:

$lo g_{4} (64) = x$

(spoiler)

Move the base ( $4$ ) to the right side and raise the $x$ as its exponent:

$64 = 4^{x}$

Since $4^{3} = 64$ :

$x = 3$

Using logarithms to solve for $x$ as an exponent

Solve for $x$ as an exponent by taking the log of both sides of an algebraic equation. This works out because if a log has the same value in its base as it does within the function, it will cancel out. Then, we are left with a logarithm on one side of the equation and an exponent lowered to be a normal number on the other side. Below is an example:

Find the value of $x$ for the following equation in terms of a logarithm:

$33 = 2^{x}$

Take the log of both sides, where $2$ is the base:

$lo g_{2} (33) = lo g_{2} (2^{x})$

This simplifies using our logarithmic rules to be:

$lo g_{2} (33) = x$

The important thing to learn from this example is that a logarithm may be used to lower $x$ from an exponent and solve for it algebraically.

Key points

Multiplication. Take each term being multiplied and put them into logarithms of the same base as a total sum: $lo g_{a} (b * c) = lo g_{a} (b) + lo g_{a} (c)$

Division. Take each term being divided and put them into logarithms of the same base as a total difference: $lo g_{a} (b / c) = lo g_{a} (b) - lo g_{a} (c)$

Exponent. Take the exponent from inside the logarithm and multiply it in front of the logarithm: $lo g_{a} (b^{c}) = c * lo g_{a} (b)$

Algebra. To use logarithms in algebra, move the base to the right side of the equation, raising what used to be there as the power of the base: $lo g_{a} (b) = c$ is simplified as $b = a^{c}$ . Lower $x$ from an exponent by taking the log of both sides of the equation.

Change of base. Change the base of a logarithm to $10$ in order to put it into a basic calculator by using the formula $lo g_{b} (a) = \frac{l o g _{10} ( a )}{l o g _{10} ( b )}$ . Alternatively, calculate a logarithm with an abnormal base in your calculator by typing “ $lo g ($ number, base $)$ ”.

Understanding logarithms

A logarithm is a function that describes the power to which a base must be raised in order to result in a certain number. This will make more sense as we understand how they are used in algebra.

For now, let’s examine the different parts of a logarithm that we will be talking about in this chapter:

$lo g_{2} (8) = 3$

Logarithm rules using parentheses

Multiplication

So, we can start out with a logarithm like this:

$lo g_{2} (8 * x)$

And rearrange it to look like this:

$lo g_{2} (8) + lo g_{2} (x)$

You’ll notice that both of the logarithms have the same base, $2$ . When you perform this expansion of logarithms, each term should have the same base.

Division

When there is division inside the parentheses of a logarithm, we follow a similar process as above but we subtract logarithms instead of adding them. We will keep all the bases the same, too.

Let’s expand the following logarithm using the same rules as multiplication, but subtracting instead of adding the terms:

$lo g_{2} (\frac{8}{x}) = lo g_{2} (8) - lo g_{2} (x)$

As you can see, the numerator is the first logarithm, then the denominator is subtracted from it.

Exponents

$lo g_{2} (x^{8}) = 8 * lo g_{2} (x)$

We remove the exponent from inside the parentheses and put it in front of the logarithm. That’s all there is to it!

Reverse rules

Rewrite the following expression as a single logarithm

$lo g_{10} (8) + lo g_{10} (7) + lo g_{10} (x)$

$lo g_{10} (8 * 7 * x) = lo g_{10} (56 x)$

Simplify the following logarithmic expression:

$3 * lo g_{6} (x)$

(spoiler)

Use the exponent rule here. The exponent rule says that we remove the exponent from inside the parentheses and multiply it outside the logarithm. The reverse of this would be restoring the exponent.

Thus, our final answer is:

$lo g_{6} (x^{3})$

Change of base

Logarithms in a graphing calculator

For a TI-84, perform a logarithmic calculation by pressing the $lo g$ button, entering the number within the $lo g$ , a comma, and then the base of the $lo g$ .

Change of base formula

If you need to calculate a logarithm with an abnormal base (a base other than $10$ ), use the following equation:

$lo g_{b} (a) = \frac{lo g _{x} ( a )}{lo g _{x} ( b )}$

This being the case, we can edit the formula:

$lo g_{b} (a) = \frac{lo g _{10} ( a )}{lo g _{10} ( b )}$

Let’s evaluate $lo g_{2} (30)$ using this formula:

$lo g_{2} (30) = \frac{lo g _{10} ( 30 )}{lo g _{10} ( 2 )} = 4.9$

Logarithms in algebra

There will be times in which you will be asked to find the value of $x$ within a given logarithmic equation. This could be similar to the following form:

$lo g_{x} (9) = 2$

To solve for $x$ , we will go over one key concept of how to use logarithms in algebra without a calculator.

$lo g_{x} (9) 993 = 2 = x^{2} = x = x$

Examples

What is the value of $x$ ?

$lo g_{2} (x) = 4$

(spoiler)

Move the base ( $2$ ) to the right side and raise the $4$ as its exponent:

$lo g_{2} (x) x x = 4 = 2^{4} = 16$

Let’s try another!

Find the value of $x$ for the following equation:

$lo g_{4} (64) = x$

(spoiler)

Move the base ( $4$ ) to the right side and raise the $x$ as its exponent:

$64 = 4^{x}$

Since $4^{3} = 64$ :

$x = 3$

Using logarithms to solve for $x$ as an exponent

Find the value of $x$ for the following equation in terms of a logarithm:

$33 = 2^{x}$

Take the log of both sides, where $2$ is the base:

$lo g_{2} (33) = lo g_{2} (2^{x})$

This simplifies using our logarithmic rules to be:

$lo g_{2} (33) = x$

The important thing to learn from this example is that a logarithm may be used to lower $x$ from an exponent and solve for it algebraically.

Key points

Multiplication. Take each term being multiplied and put them into logarithms of the same base as a total sum: $lo g_{a} (b * c) = lo g_{a} (b) + lo g_{a} (c)$

Division. Take each term being divided and put them into logarithms of the same base as a total difference: $lo g_{a} (b / c) = lo g_{a} (b) - lo g_{a} (c)$

Exponent. Take the exponent from inside the logarithm and multiply it in front of the logarithm: $lo g_{a} (b^{c}) = c * lo g_{a} (b)$

Understanding logarithms

Logarithm rules using parentheses

Multiplication

Division

Exponents

Reverse rules

Change of base

Logarithms in a graphing calculator

Change of base formula

Logarithms in algebra

Examples

Using logarithms to solve for x as an exponent

Properties of logarithms

Understanding logarithms

Logarithm rules using parentheses

Multiplication

Division

Exponents

Reverse rules

Change of base

Logarithms in a graphing calculator

Change of base formula

Logarithms in algebra

Examples

Using logarithms to solve for x as an exponent

Using logarithms to solve for $x$ as an exponent

Using logarithms to solve for $x$ as an exponent