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AMC 8
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Textbook
1. Introduction
2. Algebra (cloned)
3. Geometry (cloned)
4. Triangles
5. Combinatorics
6. Number theory (cloned)
7. Probability (cloned)
8. Combinatorics (cloned)
9. What's next? (cloned)
10. Counting
11. Arithmetic
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10. Counting
Achievable AMC 8
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Counting

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The most basic principle is multiply a*b For instance how many different ice cream combos can you make with 5 toppings and 5 flavors, 5x5=25

Permutation, Count a permutation when the order of your items matters. The easiest permutation is sets of 1, for instance, 4 runners in a race how many ways can they finish? we do n! Which is 4x3x2x1=24 different orders the racers could finish in.

Say you have 8 racers and you want to pick how many ways you can choose the top three, we use N!/(N−R)!:8!/(8−3)!=8!/5!=8∗7∗6∗5∗4∗3∗2/5∗4∗3∗2=8∗7∗6=336

Combinations Combinations are when order DOES NOT matter, for instance if ABC is the same COMBINATION as CBA. We calculate it like this: N!/(R!∗(n−r)!). It looks a lot like the permutation formula above but it the number of combinations is always smaller. (write a coin example problem here)

Principal inclusion exclusion It’s usually pretty easy to get the members of a set A and or set B, just sum up how many. But what if you want to know How many in A or B, you need to subtract the shaded region which is A and B or you will be double counting

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